Math, asked by aarzoosikarwar572, 8 months ago

for what value of k, x2-kx+9=0 does not possess real roots​

Answers

Answered by biligiri
2

Answer:

for imaginary roots

D < 0

D = b^2 - 4ac < 0

a= 1. b = -k and c = 9

(-k)^2 - 4*1*9 < 0

k^2 - 36 < 0

k^2 < 36

after plotting on number line the range of k will be ( -6 < k < 6 )

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