Math, asked by mannatkalani12, 11 months ago


If x + 1 by x =

5, find the value of x cube + 1 by x cube​

Answers

Answered by DrNykterstein
2

</p><p></p><p>\bold{\underline{\sf Given:}} </p><p>\\ </p><p> \sf  \rightarrow \quad x + \frac{1}{x} = 5 </p><p></p><p>\\ \\</p><p>

</p><p></p><p>\bold{\underline{\sf To Find:}} </p><p>\\ </p><p> \sf  \rightarrow \quad x^{3} + \frac{1}{x^{3}} = ? \\ \\</p><p></p><p>

</p><p></p><p>\bold{\underline{\sf Solution:}} </p><p>\\ </p><p>\\</p><p>

</p><p> \sf \rightarrow \quad x +  \frac{1}{x}  = 5 \\  \\  \sf \rightarrow \quad  \bigg(x +  \frac{1}{x}  \bigg)^{3}  =  {(5)}^{3}  \\  \\ \sf \quad (a  + b)^{3}   =  {a}^{3}  +  {b}^{3}  + 3ab(a + b) \\  \\ \sf \rightarrow \quad  {x}^{3}  +  \frac{1}{ {x}^{3} }  + 3 \cdot  \cancel{x} \cdot  \frac{1}{ \cancel{x}}  \left(x +  \frac{1}{x}  \right) = 125 \\  \\ \sf \rightarrow \quad  {x}^{3}  +  \frac{1}{ {x}^{3} }  = 125 - 3 \\  \\ \sf \rightarrow \quad  {x}^{3}  +  \frac{1}{ {x}^{3} }  = 122</p><p>

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