Question

for what value of Kwill the consecutive terms 2k+1,3k+3and 5k+1form an AP

Answer 1

Answer:2k + 1 = a

3k + 3 = b

5k - 1 = c

To form an AP,

a + c = 2b

2k + 1 + 5k - 1 = 2( 3k + 3)

7k = 6k + 6

k = 6

So, k = 6

Step-by-step explanation: