Question

For what value of m does the equation x2 - 12x+m=0 have real and equal roots?

​

Answer 1

Answer:

its very easy let me explain

Step-by-step explanation:

a=1,b=12,c=m

by applying b square -4ac

12 square -4(1)(m)=0

144-4m=0

4m=144

m =144 by 4

m= 36.

it's correct bro /sis

mark my answer as brainlest answer.....

thank you

all the best

Answer 2

Answer :-

The value of m is 36.

Explanation :-

The given equation is ${x}^{2} - 12x + m = 0$

This is of the form $a {x}^{2} + bx + c = 0$ where a = 1, b = -12 and c = m.

Since the roots are real and equal,

${b}^{2} - 4ac = 0 \\ = > {( - 12)}^{2} - 4m = 0 \\ = > 144 = 4m \\ = > m = \frac{144}{4} \\ = > m = 36$

•°• The value of m is 36.

#answerwithquality #BAL