For what value of m is x3-2mx2+16 divisible by x+2?
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Answered by
14
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Pljig:
The answer is m=2
no, answer will be 1. 100℅ sure..
I also proved that answer will be 1
The answer of Kiki9876. Ace
Is wrong
may be but How my answer is wrong?
I also answered, see again
Answered by
9
By remainder theorem:
f(x)=x^3-2mx^2+16
f(-2)= (-2)^3-2×m×(-2)^2+16
= -8-8m+16
= 8-8m
by factor theorem:
8-8m = 0
∆ -8m = -8
∆ m = -8\-8
∆ m = 1 [Answer]
f(x)=x^3-2mx^2+16
f(-2)= (-2)^3-2×m×(-2)^2+16
= -8-8m+16
= 8-8m
by factor theorem:
8-8m = 0
∆ -8m = -8
∆ m = -8\-8
∆ m = 1 [Answer]
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