Question

the amount of wet NaOH containing 15% water required to prepare 70 litres of 0.5 N solution is

Answer 1

answer in the pic...

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Answer 2

Given,

Wet Na OH having 15% water or 85 purity.

Molar mass of Na OH is 40g/mol.

70 liters of 0.5 N solution needs 70*0.5

                                                      = 35 moles

                                                      = 35 *40

                                                      = 1,400 g

Hence, the amount of wet NaOH is 1400 * 100/85

                                                        =16.470 * 100

                                                         =1647 g of wet Na OH