for what value of n 2^n*5^n will ends with 0 always
Answers
Answered by
1
Answer:
Step-by-step explanation:
Any number multiplied by 10 always ends in 0. (The basic test of divisibility rule to check if a number is divisible by 10 is whether the final digit of the number is 0).
Thus, for any value of n, n2 multiplied by 10 will also end in 0. As a result, the value of 10n2 will never end with 5.
Answered by
0
Answer:
For any positive integral value (integer) of n will satisfy the condition.
Step-by-step explanation:
To end with 0 the number should be divisible by 10.
Since 5*2 =10,
There should be one 5 and a 2 in the prime factorization.
So since any positive integral value (0 not included) will give a 5 and a 2,
the answer is a positive integral value.
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