For what value of n,2nx5n ends in 5
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Hey mate. ..
Let us take 2n × 5 n = 5.....which ends with 5
Therefore 10n^2 = 5
So n = 1 / root 2 .
2 ( 1 / root 2 ) × 5 ( 1 / root 2 )
= 2 / root 2 × 5 / root 2
= root 2 × 5 / root 2
= 5 ..
Let us take 2n × 5 n = 5.....which ends with 5
Therefore 10n^2 = 5
So n = 1 / root 2 .
2 ( 1 / root 2 ) × 5 ( 1 / root 2 )
= 2 / root 2 × 5 / root 2
= root 2 × 5 / root 2
= 5 ..
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