for what value of n are the 60,62,64,... and -10,-3,4,11... equal?
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when n = 15
BOth is equal to 88 so n =15
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BOth is equal to 88 so n =15
mark me as brainliest thanks
Shreya93:
Tq so much
Answered by
1
First a.p
60, 62, 64
a = 60. d = 2
Second a.p
-10, -3, 4, 11
a= -10. d = 7
N is equal.
Therefore
an = an
60+(n-1)2 = -10+(n-1)7
60+2n-2 = -10+7n-7
58+2n = -17+7n
58+17 = 7n -2n
75 = 5n
N = 15
Therefore the value of n to satisfy the above mentioned question is 15
60, 62, 64
a = 60. d = 2
Second a.p
-10, -3, 4, 11
a= -10. d = 7
N is equal.
Therefore
an = an
60+(n-1)2 = -10+(n-1)7
60+2n-2 = -10+7n-7
58+2n = -17+7n
58+17 = 7n -2n
75 = 5n
N = 15
Therefore the value of n to satisfy the above mentioned question is 15
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