Question

How many number of oxygen molecules are required to produce 220mg of carbon dioxide?

Answer 1

C + O2 ———> CO2

6.022*10^23 molecules are required to produce 44g of CO2

For 0.22g of CO2 number of oxygen molecules required is
= (0.22/44) * 6.022 * 10^23
= 0.005 * 6.022 * 10^23
= 3.011 * 10^21 molecules

Answer 2

Answer: $0.030\times 10^{23}molecules$ of oxygen

Explanation:- According to Avogadro's law, 1 mole of every gas contains $6.023\times 10^{23}$ particles and weighs equal to the molecular mass of that substance.

$C+O_2(g)\rightarrow CO_2(g)$

From the balanced chemical chemical equation:

1 mole of oxygen molecules produce 1 mole of $CO_2$ molecule.

Thus 44 g of $CO_2$ is produced from 32 g of $O_2$

Thus 220 mg or 0.22 g  $CO_2$ is produced from=$\frac{32}{44}\times 0.22=0.16g$ of $O_2$

Now 32 g of oxygen molecules contain=$6.023\times 10^{23}molecules$ of oxygen

Thus 0.16 g of oxygen molecules contain=$\frac{6.023\times 10^{23}}{32}\times 0.16=0.030\times 10^{23}molecules$ of oxygen