For what value of n,are the nth term of 2 AP's:63,65,67.....and 69,68,67.....equal?
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A=63,D=2
A(n)=A+(n-1)D
=63+(n-1)D
=63+(n-1)(2)
=63+2n-2
=61+2n --(i)
a=69,d=-1
a(n)=a+(n-1)d
=69+(n-1)(-1)
=69+(-n+1)
=69-n+1
=70-n ---(ii)
by equation (i) and (ii)
61+2n=70-n
2n+n=70-61
3n=9
n=9/3
n=3
A(n)=A+(n-1)D
=63+(n-1)D
=63+(n-1)(2)
=63+2n-2
=61+2n --(i)
a=69,d=-1
a(n)=a+(n-1)d
=69+(n-1)(-1)
=69+(-n+1)
=69-n+1
=70-n ---(ii)
by equation (i) and (ii)
61+2n=70-n
2n+n=70-61
3n=9
n=9/3
n=3
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