Question

For what value of n, are the nth terms of two APs: 63, 65, 67, . . . and 3, 10, 17, . . . equal?​

Answer 1

SOLUTION IS IN THE PICTURE. HOPE IT WILL HELP YOU.

Answer 2

We are given two different APs, and we need to find the value of n for which nth terms of both APs are equal.

nth term of first AP goes by the formula

an = 63 + (n-1)2

nth term of second AP goes by the formula

an = 3 + (n-1)7

Since both are equal, so

63 + (n-1)2 = 3 + (n-1)7

60 = 5(n-1)

12 = n-1

n = 13

So the 13th terms of both APs are equal