Question

For what value of p (-4) is a zero of polynomial x^2-2x-(7p+3)?​

Answer 1

Answer:

Step-by-step explanation:

x²-2x-(7p+3)=0

(-4)²-2(-4)-7p-3=0

16+8-3-7p=0

21-7p=0

-7p=-21

p=21/7

p=3

If p = 3 , then (-4) is a factor of p(x)

Answer 2

X²-2x-(7p+3)=0

(-4)²-2(-4)-7p-3=0

16+8-3-7p=0

21-7p=0

-7p=-21

p=21/7

p=3

If p = 3 , then (-4) is a factor of p(x)