Question

for what value of p, (-4) is a zero of the polynomial x^2-2x-(7p+3) ?​

Answer 1

Answer:

p= 3

Step-by-step explanation:

Put the value of x as -4 in the given expression and equate it with 0.

Let f(x)=x^2-2x-(7p+3)

so,f(-4)=0

then, f(-4)=(-4)^2-2*(-4)+(7p+3)

0=16+8-7p-3

7p=21

p=3

Hope this will help you.