Question

For what value of p ,-4is the zeroes of the polynomial x²-2x-(7p+3)

Answer 1

By putting x= -4

(-4)^2 -2(-4) -(7p+3) = 0
so, 16+8-7p-3 = 0
    so, 24-3+7p = 0
            so, 7p = -21
              so, p = -3

Answer 2

Hey,,
x = -4
→x²-2x-(7p+3) = 0
→(-4)²-2(-4)-(7p+3) = 0
→16+8-7p-3 = 0
→24-7p-3 = 0
→21-7p = 0
→-7p = -21
→ p = -21/-7
so, p = 3