for what value of p are 2p+1 ,13 ,5p-3,the three consecutive terms of an arithmetic progression?
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Hi dear!!!
common difference = a2-a1
so a2-a1 = a3-a2
2a2 = a1+a3
2*13 = 2p+1 +5p-3
26=7p-2
p= 28/7
p = 4
hope it help you !!!
thanks!!
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