Question

For what value of p does px^2+4x+1=0 has real eoots

Answer 1

Answer:

D = b^2 - 4ac

D = 4^2 - 4×p×1

D = 16 - 4p

has real roots

D = 0

16 - 4p = 0

-4p = -16

p = 4

Answer 2

Answer:

p<=4

Step-by-step explanation:

D>=0

b^2-4ac>=0

4^2-4p>=0

16-4p>=0

4-p>=0

p<=4

**HOPE IT HELPS**