Question

for what value of p the equation 2x+3y=1 and (2k-1)x+(k+1)y=2k+3 are inconsistent​

Answer 1

(2k-1)x+(k-1)y = 2k +1

3x+y=1...(1)

(2k−1)x+(k−1)y=2k+1..(2)

Now rearranging eq1 and eq2 will get

3x+y−1=0...(3)

(2k−1)x+(k−1)y−(2k+1)=0..(4)

Now compare with

⇒3k−3=2k−1

⇒3k−2k=−1+3

⇒k=2

Hence k=2 is the value