Question

for what value of P, the quadratic equation P² + 8x - 2 = 0 has real roots
incorrect answer will be reported

Answer 1

Hi...☺

Here is your answer....✌

Equation : Px²+8x-2 = 0

a = P , b = 8 , c = -2

For real roots,

Discriminant , D ≥ 0

b²-4ac ≥ 0

8²-4×(P)×(-2) ≥ 0

64+8P ≥ 0

8P ≥ -64

=> P ≥ -8

Answer 2

Hey... Mate here's ur solution !!

We have,

a = P
b = 8
c = -2


Now,
D = b² - 4ac

= ( 8 )² - 4 ( P ) ( - 2 )

= 64 + 8P



For real roots,

( Use attachment )



Hope it might be helpful !!