Question

For what value of p the quadratic equation px2 +8x-2 =0 has real roots

Answer 1

if the equation has real roots then it satisfy that b^2-4ac=0
and here a is equals to p, b is equals to 8 and C is equals to minus 2.
(8)^2-4(p)(-2)=0
64+8p=0
8p=-64
p=-8

Answer 2

The value of p is "- 8".

Step-by-step explanation:

The given quadratic equation:

$px^2+8x-2 =0$

To find, the value of p = ?

Here, a = p, b = 8 and c = - 2

∴ $D=b^{2} -4ac$

$=8^{2} -4(p)(-2)$

$=64+8p$, has real root

∴ $64+8p=0$

⇒ p = - 8

Hence, the value of p is "- 8".