For what value of p will the following pair of linear equations have infinitely many
solutions
(p-3)x+3y =p
px+py = 12
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Answer:
Step-by-step explanation:
for infinitely many solution, a1/a2=b1/b2=c1/c2
a1=p-3
a2=p
b1=3
b2=p
c1=p
c2=12
therefore,
a1/a2=b1/b2=c1/c2
take just,a1/a2=b1/b2
p-3/p=3/p
p-3=3/p*p
p and p will get cancelled
so,
p-3=3
p=3+3
p=6
hope you like it
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