Math, asked by pateldhruti22506, 8 months ago

For what value of p will the following pair of linear equations have infinitely many
solutions
(p-3)x+3y =p
px+py = 12​

Answers

Answered by vishalprabu24
0

Answer:

Step-by-step explanation:

for infinitely many solution, a1/a2=b1/b2=c1/c2

a1=p-3

a2=p

b1=3

b2=p

c1=p

c2=12

therefore,

a1/a2=b1/b2=c1/c2

take just,a1/a2=b1/b2

p-3/p=3/p

p-3=3/p*p

p and p will get cancelled

so,

p-3=3

p=3+3

p=6

hope you like it

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