Question

for what value of P will the following set of equations has no solution (2P-1)x-(p-1)y=2p+1; y+3x-1=0

Answer 1

if these equation has no solution then
$\frac{a1}{a2} = \frac{b1}{b2} \: is \: not \: equal \: to \: \frac{c1}{c2} \\ \frac{2p - 1}{3} = \frac{ - (p - 1)}{1} is \: \: not \: equal \: = \frac{ - (2p + 1)}{ - 1} \\ 2p - 1 = - 3p + 3 \\ 2p + 3p = 3 + 1 \\ 5p = 4 \\ p = \frac{4}{5} \: \: ans \\ \\ - (p - 1) \: \: is \: not \: equal \: (2p + 1) \\ - p - 2p \: \: is \: not \: equal \: to \: + 1 - 1 \\ p \: \: is \: not \: equal \: to \: zero$