Question

for what value of the K will the following pair of linear equation have no solution 2x+3y=1,(2k+1) x+(k+1)y=2k+3

Answer 1

hey mate hers is ur ans

no solution is in the case when the lines are parLlel =a1/a2=b1b2is nt equalto c1/c2

2/1=3/k+1=/2k+1/2k+3
2k+2=3
2k=1
k=1/2


Hope this helps u

Answer 2

Heya !!!




2X + 3Y = 1



2X + 3Y - 1 = 0 ----------(1)



And,


(2K +1 )X + (K+1)Y = 2K+3



(2K+1)X + (K+1)Y - (2K+3) = 0 ------(2)




These equations are of the form of A1X + B1Y+C1 = 0 and A2X + B2Y + C2 = 0




Where,



A1 = 2 , B1 = 3 and C1 = -1




And,


A2 = (2K+1) , B2 = (K+1) and C2 = -2K-3





For no solution we must have,




A1/ A2 = B1/B2 # C1/C2 [ Where # stand for not equal]



2/ 2K+1 = 3/K+1




2(K +1 ) = 3 (2K+1)




2K +2 = 6K + 3





6K -2K = 2-3



4K = -1




K = -1/4





★ HOPE IT WILL HELP YOU ★