Question

For what value of x is derivative of x^3 equal to derivative of x^2+x

Answer 1

Answer: x=1 , x=-1/3

Step-by-step explanation: Derivative of x^3 = 3x^2

Derivative of x^2+x = 2x+1

3x^2 = 2x+1

3x^2 - 2x -1=o

Factorising the equation:

3x(x-1)+1(x-1)=0

Therefore , x=1, -1/3

Answer 2

Answer:

x = 1, -1/3

Step-by-step explanation:

According to question

Derivative of x³ equal to derivative of x² + x

So d/dx(x³) = d/dx(x² + x)

3 × x² = (2 × x) + 1

3x² - 2x - 1 = 0

3x² - 3x + x - 1 = 0

3x(x - 1) + (x - 1) = 0

(3x + 1) (x - 1) = 0

If (3x + 1) = 0

x = - 1/3

If (x - 1) = 0

x = 1

So value of x = 1, -1/3

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