Question

for what value of x is sin x = cos 19°, where 0°< x < 90°?

Answer 1

Answer:

Sin x = cos 19° ; 0° < x < 90°

cos is the complementary of sine. This means that the value of x in sin x and the value of 19° in cos 19° adds up to 90°

x + 19° = 90°

x = 90° - 19°

x = 71°

sin 71° = cos 19°

0.9455 = 0.9455

Value of x = 71°

Answer 2

Answer:

Step-by-step explanation:

SIN X=COS 19°

SIN X=COS(90-71)

X=71