Question

for what value of y are the points P(1, 4) Q(3, y) and R(-3, 16) are collinear. ​

Answer 1

Answer:

When, y = -2, the given points are collinear.

Step-by-step explanation:

P(1,4),(3, y) and R(-3,16) are the given points. Then

(x = 1, y; = 4), (x3 = 3, y = y) and (x, =-3, y, = 16)

It is given that the points P, Q and R are collinear.

Therefore,

x1 (y2-y3)+ x2(y3 -y1)+ x3(y1-y2)=0

= 1(y-16)+3(16-4)+(-3)(4-y)=0

=1(y-16)+3(12)-3(4-y)=0

=y-16+36-12+3y= 0

=8+4y = 0

4y = -8

y= -8/4= -2

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