Question

For what value of y are the points P(1,4) , Q(3,y) and R(-3,16) are collinear

Answer 1

put area =0 then apply area of triangle
0=1÷2|1×y+3×16+(-3×4)-1×16+3×y-3×4|
0=|y+48-12-16+3y-12|
|4y+8|=0
4y=-8
y=-2

Answer 2

Answer:

y=2

Step-by-step explanation:

Put area =0 then apply area of triangle

=0=1÷2|1×y+3×16+(-3×4)-1×16+3×y-3×4|

=0=|y+48-12-16+3y-12|

=|4y+8|=0

=4y=-8

=y=-2