Question

For what value(s) of ‘a’ quadratic equation 30 2 − 6 + 1 = 0 has no real​

Answer 1

Answer:

30x²-b×+1<0

36-120<0

×=94/-95

Answer 2

GivEn :-

A quadratic Equation + 30ax² − 6x + 1 = 0

To FinD :-

To Find the discriminant and find the Solution.

CalculaTioN :-

To Find the discriminant of the Quadratic Equation.

30ax² - 6x + 1 = 0

Discriminant

$\begin{gathered} \sf{ {( - 6)}^{2} }{} - 4(30a)(1) < 0 \\ \\ {( - 6)}^{2} - 4(30a)(1) < 0 \\ \\ \sf{36 - 120a < 0}{} \\ \\ \sf{36 \ < 120a}{} \\ \\ 36 < 120a \\ \\ \sf{120a > 36}{} \\ \\ \sf{a > \frac{36}{120} }{} \\ \\ a > \frac{3}{10} \end{gathered}$

Hence for a value of 'a' greater than 3/10 given quadratic Equation have no teal roots

More To KnoW :-

For a Given quadratic Equation.

Two distinct Real roots

★ Discriminant b²-4ac > 0

Two equal Real roots.

★ Discriminant b²- 4ac = 0

No Real Roots

★ Discriminant b²- 4ac < 0