Math, asked by SidTheLoser, 4 months ago

For what value(s) of ‘a’ quadratic equation 30ax^2
− 6x + 1 = 0 has no real
roots?​

Answers

Answered by mohdadilansari02
2

Answer:

a=6/5

Step-by-step explanation:

x = 1 \frac{1}{6}

put in eqation

30a \frac{1}{6}^{2}   \\ 5a = 6 \\ a = 6 \frac{1}{5}

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