Question

For what value(s) of 'a' quadratic equation 3ax^2 - 6x + 1 = 0 has no real roots ?






I'm facing problem in how you can find answers for not equal to questions and how to represent them and solve them​

Answer 1

Answer:

3

Step-by-step explanation:

Since it has no real root

D<0

put a= 3a,b=-6,c=1.

-b²-4ac

(-6)²-4(3a)(1)<0

36-12a

12a<36

a>36/12

a>3

Answer 2

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