Question

For what value(s) of k, the roots of the quadratic
equation (k + 4)x2 + (k + 1)x + 1 = 0 are
equal?​

Answer 1

Answer:

d=0

b²-4ac=0

k²+1+2k-4k-16=0

k²-2k-15=0

k²+3k-5k-15=0

k(k+3)-5(k+3)=0

(k+3)(k-5)=0

k=5,-3