For what values of a does the pair of equation 2x+ 3y =7 and( a- 1)x+(a+1)y=3a-1 have infinite many solution?
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Answer:
Firstly solve bracket
Make it simple eqn
Step-by-step explanation:
2x+3y-7=0
(a-1) x+(a+1)-3a-1=0
a1/a2=2/a-1
b1/b2=3/a+1
C1/c2=-7/-3a-1
Compare a1/a2, b1/b2,c1/c2
2/a-1=3/a+1=-7/+(3a-1)
2a+2-3a-3=9a
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