Question

For what values of 'a' the quadratic equation 9 x square - 3a x + 1 is equal to zero has equal roots?​

Answer 1

Step-by-step explanation:

discriminant should be zero for equal root

so

${b}^{2} - 4ac$

(3a) square - 4 *9* 1

$9 {a}^{2} - 36 = 0$

$9 {a}^{2} = 36$

${a}^{2} = 4$

$a = 2 \: or - 2$

heres your answer