Question

For what values of k does the quadratic equation for x square - 12 x minus k is equal to zero has no real roots

Answer 1

sorry for scraching

Answer 2

The value of k is less than -36.

Step-by-step explanation:

Given : The quadratic equation $x^2-12x-k=0$ has no real roots.

To find : For what values of k ?

Solution :

When the quadratic equation $ax^2+bx+c=0$ has no real roots then discriminant is less than zero.

i.e. $D=b^2-4ac<0$

Here, a=1, b=-12 and c=-k

Substitute the values,

$(-12)^2-4(1)(-k)<0$

$144+4k<0$

$4k<-144$

$k<-\frac{144}{4}$

$k<-36$

Therefore, the value of k is -36.

#Learn more

Which of the following has two distinct real roots? (a) 2x²-3√2x+9/4=0 (b) x²+x-5=0 (c) x²+3x+2√2=0 (d) 5x²-3x+1=0

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