Question

The sum of the digits of a 3 digit number is 11. What is the product od the digits

Answer 1

Answer:

Let the number be abc. Given : a+b+c =11

1. Per statement 1, the number is divisible by 5. The possible values are 830, 425 etc. The product can thus be 8*3*0=0 or 4*2*5 = 40. Thus this statement is not sufficient.

2. Per statement 2, the possible values are 425, 632, 218 . The product can be 4*2*5=40 or 6*3*2=36 or 2*1*8=16. Thus this statement is not sufficient.

Combining 1 and 2 , the only number that is divisible by 5 and has hundred's digit twice of the ten's digit = 425 and the product is 40. Thus C is the correct answer.

Step-by-step explanation: