Question

for what values of K equation 9 X square + 6 kX + 4 equal to zero has equal roots​

Answer 1

Answer:

bKaieixnakdkekakzma

Answer 2

${\bigstar}$SOLUTION${\bigstar}$

9x² + 6kx + 4 = 0

it is in the form of ax² + bc + c = 0

here ,

• a = 9
• b = 6k
• c = 4

given that the equation has equal roots

so

➥∆ = 0

[ ∆ = b² - 4ac ]

➥b² - 4ac = 0

➥(6k)² - 4(9)(4) = 0

➥36k² - 144 = 0.

➥36k² = 144

➥k² = $\frac{144}{36}$

➥k = $\sqrt{ \frac{144}{36} }$

➥k = $\sqrt{ \frac{ {12}^{2} }{ {6}^{2} } }$

➥k = $\sqrt{ { (\frac{12}{6} )}^{2} }$

➥k = 2