Question

For what values of k if x = 2, y=3 is a solution of (k+1)x-2(2k+3)y-1=0

Answer 1

Answer:

Step-by-step explanation:

X=2,y=3

(K+1)x-2-2 (2k+3)y-1=0

(K+1)2-2 (2k+3)3-1=0

2k+2-4k-6 (2)=0

2k+2-4k-12=0

-2k-10=0

-2k=10

K=-5