Question

for what values of k the equation 2x+ky=5 and 3x-3y=6 have unique solution​

Answer 1

Answer:

The given equation is

2x+ky=5, 3x+3y=5

2x+ky-5=0, 3x+3y-5=0

These equation are of the form

a1x+b1y+c1=0 ,a2x+b2y+c2=0

where a1=2,b2=k, c1=-5

a2=3, b2=-3, c2=-6

for unique solution,we must have:

a1/a2 is not equal to b1/b2

2/3is not equal to k/-3

k is not equal to -2

this happen when k is not equal to- 2

Thus,for all real values of k other than -2

,the given system of equation will have a

unique solution.