Question

for what values of k, the roots of the equation x2 + 4x + k=0 are real?​

Answer 1

Answer:

x = 0

Step-by-step explanation:

0× 2 + 4×0 + k = 0

k = 0

complete

Answer 2

Given Equation

• x² + 4x + k = 0

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To find

• Value of k.

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Solution

• In case of real roots, discriminant of the equation is more than or equal to 0.

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★ D = b² - 4ac

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→ D = (4)² - 4(1)(k)

→ D = 16 - 4k

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• Here

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★ D ≥ 0

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→ 16 - 4k ≥ 0

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→ -4k ≥ -16

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→ k ≥ -16/-4

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→ k ≥ 4

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Hence,

• The value of k is more than or equal to 4.

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