Question

for what values of K will the pair of linear equation kx + 2y is equal to 5 and 3 X + Y is equal to 1 have unique solution?​

Answer 1

$\large{explanation}$

given

kx+2y=5

3x+y=1

for unique solution

$\frac{a1}{a2} not = to \frac{b1}{b2}$

like this

a1/a2≠b1/b2

comparing this we get

$\frac{k}{3} not = to \frac{2}{1}$

k≠6

the value of k for which the equation has unique solution is 6

$\large{vergilmustdie}$

Answer 2

Hie!!

Given linear equations are

kx + 2y = 5

3x + y = 1

For Unique solution

k/3 ≠ 2/1 ≠ 5/1

k/3 ≠ 2/1

k ≠ 6

K≠6 Means k can take any value except 6

k € R - { 6 }