Question

the average of 1,3,5,7,9,11.....upto 25th terms of

Answer 1

Answer:

Step-by-step explanation:

→ The number of terms is

→N = (25 - 1) / 2  + 1 = 13

The sum of terms, which is the arithmetic progression with difference 2, is:

→S = (1 + 25) × 13 ÷ 2 = 13 × 13

The average is:

→ A = S / N = 13 × 13 / 13 = 13

So, to calculate the average of arithmetic progression was needed to calculate the number of terms N, the average arithmetic progression is the average of first and last term:

→A = (1 + 25) / 2 = 13

Answer 2

Step-by-step explanation:

=(1+3+5+.....+49)/25

=625/25

=25