Math, asked by Anonymous, 2 months ago

for what values of m will the equation have real and distinct roots​

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Answers

Answered by MonoranjanDas
0

Answer:

m \geqslant  \frac{ - 1}{2}

Step-by-step explanation:

The equation has real and distinct roots

So

b {}^{2}  - 4ac \geqslant 0

 = > (2(1 + 2m)) {}^{2}  - 4 \times 2m(1 + 2m) \geqslant 0

 =  > 4(1 + 2m) {}^{2}  - 8m(1 + 2m) \geqslant 0

 =  > 4(1 + 2m \geqslant 0

 =  > 1 + 2m \geqslant 0

so \:  \: m \geqslant  \frac{ - 1}{2}

so \: for \: m \geqslant  \frac{ - 1}{2} \: equation \: has \: real \: and \: distinct \: roots

 = > 4(1 + 2m)(1 + 2m - 2m) \geqslant 0

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