Question

For what values of p are 2p + 1, 13, 5p – 3 are three consecutive terms of an A.P.?

Answer 1

Step-by-step explanation:

Here's your answer...

Answer 2

p = 4.

Step-by-step explanation:

If 2p + 1, 13, 5p – 3 are in an AP there will be equivalent to a-d, a and a+d respectively.

 So let's take a = 13,

 Then d = 13 - (2p+1)

     d = 12 - 2p  

 So we have 5p - 3 = a+d

  5p - 3 = 13 + 12 - 2p

   7p = 28

  p = 28/7 = 4

 So 2p+1, 13, 5p–3 will be in an AP when p = 4.