Write the expression for the common difference of an A.P. whose first term is a and nth term is b.
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Answer:
Step-by-step explanation:
Since ,
a= first term and Tn = b
Tn= a + (n-1)d
Therefore,
b = a + (n-1)d
b - a = (n-1)d
b-a/ n- 1= d
Hence common difference, d, is
b-a/n-1
:)
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