For what values of x are the numbers(x+9,(x-6),and 4 in GP?
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in G.P b/a=c/b
=>x-6/x+9 = 4/x-6
=>x^2+36-12x=4x+36
=> x^2-16x=0
=>x (x-16)=0
=>x=0 or x=16
but x=0 is not possible
therefore x=16
=>x-6/x+9 = 4/x-6
=>x^2+36-12x=4x+36
=> x^2-16x=0
=>x (x-16)=0
=>x=0 or x=16
but x=0 is not possible
therefore x=16
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