Question

For what values of x, x²-5x+6≤0​

Answer 1

Answer:

x2, 3

Step-by-step explanation:

x

$x {}^{2} - 5x + 6 \leqslant 0 \\ x {}^{2} - 3x - 2x + 6 \leqslant 0 \\ x(x - 3) - 2(x - 3) \leqslant 0 \\ here \: both \: the \: roots \: are \: positive\\( x - 3)(x - 2) = 0 \\ x = 2 \: \: \: \: x = 3$

x=2,3