Question

for what valur if R the net resistance will of the circuit will 18 ohm​

Answer 1

Answer:

16Ω

Explanation:

Explanation: Here 10Ω is in parallel with 10Ω

∴ R across Pɸ = 10 + (10 || 10)

= 10 + {(10 × 10) / (10 + 10)} = 15Ω

15 Ω is parquet with 10Ω hence equivalent resistance is {(15 × 10)/(15 + 10)} = 6Ω

Hence circuit reduces to RAB = 10 + [R || (10 + 6)]

= 10 + [R || 16]

given RAB = 18Ω

∴ 18 – 10 = R || 16 8

= {(R × 16)/(R + 16)}

∴ R + 16 = 2R 16

= R R = 16Ω.