Question

For which of the following process, ∆S is negative?
(a) H₂ (g) → 2 H(g)
(b) 2SO₃ (g) → 2SO₂(g) + O₂ (g)
(c) N₂ (4????)□(→┴compressed )N₂ (2????)
(d) C(diamond) → C (graphite)

Answer 1

Answer:

ANSWER

(A)When we increase the temperature of a gas then randomness is increased due to kinetic energy gained by molecules.

So, \DeltaΔS>0S>0

(B)When pressure increases then molecules of gas will come closer and intermolecular distance decreases so entropy will also decrease.

and \DeltaΔS<0S<0

(C)When Diamond is converted into graphite when it is heated to 1500^oC1500

o

C and entropy is increased so \DeltaΔS>0S>0

(D)H_2H

2

molecule is converted into atoms, So entropy will increase.

So \DeltaΔS>0S>0

Answer 2

Hello Friend..!!

The answer of your question is..!!

Option.A

Thank you..!!