Question

for which of the following reactions, Kp=Kc?

Answer 1

Option (b) is right.

Since, Kp=Kc(RT)^-ng

Here, ng= 2-2=0

So, from the relationship of Kp &Kc....

Kp=Kc

Answer 2

For the reaction, $N_2+O_2\rightarrow 2NO$ , $K_p=K_c{/tex]</p><p><strong>Explanation:</strong></p><p>Relation of [tex]K_p$ with $K_c$ is given by the formula:

$K_p=K_c(RT)^{\Delta ng}$

Where,

$K_p$ = equilibrium constant in terms of partial pressure

$K_c$ = equilibrium constant in terms of concentration

R = Gas constant

T = temperature

$\Delta n_g$ = change in number of moles of gas particles = $n_{products}-n_{reactants}$

Thus $K_p=K_c$  when ${\Delta ng}=0$

For $N_2+O_2\rightarrow 2NO$, thus $\Delta n_g=(2-2)=0$

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