Question

For which pairs of functions is (f circle g) (x) = 12 x? f(x) = 3 – 4x and g(x) = 16x – 3 f(x) = 6x2 and g (x) = StartFraction 2 Over x EndFraction f (x) = StartRoot x EndRoot and g(x) = 144x f(x) = 4x and g(x) = 3x

Answer 1

Answer:

the answer is B

Step-by-step explanation:

Answer 2

Given:

1. f(x) = 3 – 4x and g(x) = 16x – 3

2. f(x) = 6x2 and g (x) = StartFraction 2 Over x EndFraction

3. f(x) = StartRoot x EndRoot and g(x) = 144x

4. f(x) = 4x and g(x) = 3x

To find: For which pairs of functions is (f circle g) (x) = 12 x.

Solution:

1.

For the given set f(x)=3-4x and g(x)=16x-3, (fog)(x) can be caluculated as follows.

$(fog)(x) = 3-4(16x - 3)$

              $= 3-64x+12$

              $= 15-64x$

2.

For the given set f(x) = 6x2 and g (x) = StartFraction 2 Over x EndFraction, (fog)(x) can be caluculated as follows.

$(fog)(x) = 6(\frac{2}{x} )^{2}$

             $= \frac{24}{x^{2} }$

3.

For the given set f(x) = StartRoot x EndRoot and g(x) = 144x, (fog)(x) can be caluculated as follows.

$(fog)(x) = \sqrt{144x}$

              $= 12\sqrt{x}$

4.

For the given set f(x) = 4x and g(x) = 3x, (fog)(x) can be caluculated as follows.

$(fog)(x) = 4(3x)$

             $=12x$

Hence, when f(x)=4x and g(x)=3x, the value of (fog)(x)=12x.

Therefore, for f(x)=4x and g(x)=3x is (f circle g) (x) = 12 x.